Table of Contents

Infosys Coding And Pseudo-code Questions 2024

Practice the top 10 Infosys Coding and Pseudo-code Questions uploaded to crack the Infosys exam on the first attempt. These coding questions will evaluate a candidate’s problem-solving abilities, logical thinking, and proficiency in programming languages. The questions range from simple data structure and algorithm problems to more complex ones involving real-world scenarios. This blog focuses on the Top 13 Infosys Coding Questions and Answers for the examination and 10 Coding Questions for specialist programmers in 2024. We have also uploaded Infosys Pseudocode questions with answers here.

Top IT firms like Infosys require coding skills and problem-solving skills for their hiring process for 2024. These skills are mandatory for the candidates applying for the job in Infosys and are used to evaluate during the Infosys interview and online test. The Pseudocode round is one of the important rounds in the Infosys coding questions in 2024. Through this Pseudocode round, they will analyze the candidate’s ability to write the algorithmic solutions with the simplified code.

Infosys coding questions often test a candidate’s understanding of concepts like arrays, strings, linked lists, trees, recursion, and dynamic programming. Solving these questions efficiently and effectively is crucial for aspiring candidates to showcase their coding skills and stand out in the competitive hiring process.

Infosys Pseudocode Questions 2024

Pseudo-code in data science, is a step-by-step description of the computer algorithm. In short, It is the high-level, language-agnostic representation of the algorithm. It indicates how to write down the algorithm’s steps in a language-agnostic manner.

Furthermore, it is useful in the early stages of software development and aids the programmers to organize and structure the programs before writing the actual code. This will also help developers focus on the program’s logic and flow. Pseudo-code will use programming language such as loops, conditionals and variables, and English words and phrases.

The Infosys Pseudo-code round has 5 questions, to be completed in 10 minutes. Pseudo-code is considered the representation of the algorithm code in Java, C, and C++. The difficulty level of the Infosys Pseudo-code Questions is moderate-high. Pseudo-code refers to the algorithm that is displayed in the coding format.

Check out the Top 10 Infosys Pseudo-code questions with answers in 2024. Solve these pseudo-code questions and crack the Infosys interview and exam.

10 Infosys Pseudo-code Questions With Answers 2024

The top 10 Infosys Pseudo-code questions are added here for your reference. Candidates preparing for the Infosys interview can understand and practice the Infosys Pseudo-code questions provided below.

1. What will be the output of the pseudocode given here?

public class Main {
    public static void main(String[] args) {
        String names[] = new String[5];
        for(int x = 0; x < args.length && x < names.length; x++) {
            names[x] = args[x];
        }
        if (args.length >= 3) {
            System.out.println(names[2]);
        } else {
            System.out.println("Not enough arguments provided");
        }
    }
}

Ans.

Scenario 1: Exactly 5 Arguments

Command:

java Main one two three four five

Output:

three

Scenario 2: Fewer Than 3 Arguments

Command:

java Main one two

Output:

Not enough arguments provided

Scenario 3: More Than 5 Arguments

Command:

java Main one two three four five six

Output:

three

Scenario 4: Exactly 3 Arguments

Command:

java Main one two three

Output:

three

Scenario 5: No Arguments

Command:

java Main

Output:

Not enough arguments provided

These outputs correspond to the improved version of the program which includes a check to ensure there are at least 3 arguments before accessing names[2].

2. What will be the output of the Pseudo Code provided below?

#include <stdio.h>
int main()
{
    float i;
    i = 1;
    printf("%f", i);
    return 0;
}

Ans. Output

1.000000

3. What will be the output of the pseudocode given here?

#include <stdio.h>
int main()
{
    int num = 987;
    int rem;
    while(num!=0)
    {
        rem = num % 4;
        num = num / 10;
    }
    printf("%d",rem);
}

Ans. Output

1

4. What will be the output of the pseudo-code provided here?

#include<stdio.h>
int main(){
    float x = 0.0;
    long int y = 10;
    printf("%d", sizeof(x) == sizeof(x+y));
    return 0;
}

Ans. Output

1

5. What will be the output of the pseudocode below?

#include<stdio.h>
int main()
{
int go = 5.0, num = 1*10;
do 
{
num /= go;
} while(go--);
printf ("%d\n", num);
return 0;
}

Ans. Output

0

6. What is the output of the program given below?

#include<stdio.h>
int main()
{
    int any = ' ' * 10;
    printf("%d", any);
    return 0;
}

Ans. Output

320

7. Write the output for the given program.

#include<stdio.h>
int main(){
    float x = 0.0;
    long int y = 10;
    printf("%d", sizeof(y) == sizeof(x+y));
    return 0;
}

Ans.

0

8. What is the output of the following program?

#include<stdio.h>
int main() 
{
    typedef int num;
    num bunk = 0.00;    
    printf("%d", bunk);
    return 0;
    
}

Ans.

0

9. What is the output?

#include<stdio.h>
int main()
{
    int a = 100;
    printf("%0 %x", a);
}

Ans. Output

100 64 

%d: 100 is printed in decimal format.%x: 100 is printed in hexadecimal format. In hexadecimal, 100 is represented as 64.

10. What is the output?

#include<stdio.h>
int main()
{
    for (int x = 10; x >= 0; x--) {
        int z = x & (x >> 1);
        if (z)
            printf("%d ", x);
     }
    
}

Ans.

Output

10 9 8 7 6 5 4 3 2 1

13 Infosys Coding Questions and Answers 2024

In Infosys Exam, they have 3 Infosys coding questions, to be completed in 3 hours. So, candidates should practice the Infosys coding questions and answers for the Infosys Exam. Check out the table below to learn more about the difficulty level of the Infosys Coding Question.

Applicants of the Infosys examination can refer to the coding questions and answers added here. Check the Infosys coding questions and answers, and improve your coding skills.

1. Write a program to arrange the given number to form the biggest number.

Ans.

Python

from functools import cmp_to_key

def compare(x, y):
    # Compare combined numbers to determine order
    if x + y > y + x:
        return -1
    elif x + y < y + x:
        return 1
    else:
        return 0

def largest_number(nums):
    # Convert numbers to strings for easy concatenation
    str_nums = [str(num) for num in nums]
    # Sort numbers using custom comparator
    str_nums.sort(key=cmp_to_key(compare))
    # Join sorted numbers to form the largest number
    largest_num = ''.join(str_nums)
    # Edge case for leading zeros
    return largest_num if largest_num[0] != '0' else '0'

# Example usage
numbers = [3, 30, 34, 5, 9]
print("The largest number is:", largest_number(numbers))

Output

The largest number is: 9534330

Java

import java.util.Arrays;
import java.util.Comparator;

public class LargestNumber {

    // Custom comparator to decide the order based on concatenation
    private static class NumberComparator implements Comparator<String> {
        @Override
        public int compare(String x, String y) {
            String order1 = x + y;
            String order2 = y + x;
            return order2.compareTo(order1); // reverse order for descending
        }
    }

    public static String largestNumber(int[] nums) {
        // Convert int array to String array
        String[] strNums = Arrays.stream(nums)
                .mapToObj(String::valueOf)
                .toArray(String[]::new);

        // Sort array using custom comparator
        Arrays.sort(strNums, new NumberComparator());

        // Edge case: Check if the largest number is 0
        if (strNums[0].equals("0")) {
            return "0";
        }

        // Join sorted array to form the largest number
        StringBuilder largestNum = new StringBuilder();
        for (String num : strNums) {
            largestNum.append(num);
        }

        return largestNum.toString();
    }

    public static void main(String[] args) {
        int[] numbers = {3, 30, 34, 5, 9};
        System.out.println("The largest number is: " + largestNumber(numbers));
    }
}

Output

The largest number is: 9534330

.NET

using System;
using System.Linq;

public class LargestNumber
{
    // Custom comparator to decide the order based on concatenation
    public class NumberComparer : IComparer<string>
    {
        public int Compare(string x, string y)
        {
            string order1 = x + y;
            string order2 = y + x;
            return order2.CompareTo(order1); // reverse order for descending
        }
    }

    public static string LargestNumberFromArray(int[] nums)
    {
        // Convert int array to string array
        var strNums = nums.Select(num => num.ToString()).ToArray();

        // Sort array using custom comparator
        Array.Sort(strNums, new NumberComparer());

        // Edge case: Check if the largest number is 0
        if (strNums[0] == "0")
        {
            return "0";
        }

        // Join sorted array to form the largest number
        return string.Join("", strNums);
    }

    public static void Main(string[] args)
    {
        int[] numbers = { 3, 30, 34, 5, 9 };
        Console.WriteLine("The largest number is: " + LargestNumberFromArray(numbers));
    }
}

Output

The largest number is: 9534330

2. Find the next permutation of the given string in the Program

Ans.

Python

def next_permutation(s):
    # Convert string to list for mutability
    arr = list(s)
    n = len(arr)

    # Step 1: Find the largest index i such that arr[i-1] < arr[i]
    i = n - 1
    while i > 0 and arr[i - 1] >= arr[i]:
        i -= 1

    # If no such index exists, the permutation is the last permutation
    if i == 0:
        return ''.join(sorted(arr))

    # Step 2: Find the largest index j such that arr[j] > arr[i-1]
    j = n - 1
    while arr[j] <= arr[i - 1]:
        j -= 1

    # Step 3: Swap arr[i-1] with arr[j]
    arr[i - 1], arr[j] = arr[j], arr[i - 1]

    # Step 4: Reverse the suffix starting from index i
    arr[i:] = arr[n - 1:i - 1:-1]

    return ''.join(arr)

# Example usage
s = "123"
print("Next permutation of", s, ":", next_permutation(s))

Output

Next permutation is: 536479

Java

import java.util.Arrays;

public class NextPermutation {

    public static String nextPermutation(String s) {
        char[] arr = s.toCharArray();
        int n = arr.length;

        // Step 1: Find the largest index i such that arr[i-1] < arr[i]
        int i = n - 1;
        while (i > 0 && arr[i - 1] >= arr[i]) {
            i--;
        }

        // If no such index exists, the permutation is the last permutation
        if (i == 0) {
            Arrays.sort(arr);
            return new String(arr);
        }

        // Step 2: Find the largest index j such that arr[j] > arr[i-1]
        int j = n - 1;
        while (arr[j] <= arr[i - 1]) {
            j--;
        }

        // Step 3: Swap arr[i-1] with arr[j]
        char temp = arr[i - 1];
        arr[i - 1] = arr[j];
        arr[j] = temp;

        // Step 4: Reverse the sequence from arr[i] to arr[n-1]
        reverse(arr, i, n - 1);

        return new String(arr);
    }

    private static void reverse(char[] arr, int start, int end) {
        while (start < end) {
            char temp = arr[start];
            arr[start] = arr[end];
            arr[end] = temp;
            start++;
            end--;
        }
    }

    public static void main(String[] args) {
        String s = "534976";
        System.out.println("Next permutation is: " + nextPermutation(s));
    }
}

Output

Next permutation is: 536479

.NET

using System;

public class NextPermutation
{
    public static string GetNextPermutation(string s)
    {
        char[] arr = s.ToCharArray();
        int n = arr.Length;

        // Step 1: Find the largest index i such that arr[i-1] < arr[i]
        int i = n - 1;
        while (i > 0 && arr[i - 1] >= arr[i])
        {
            i--;
        }

        // If no such index exists, the permutation is the last permutation
        if (i == 0)
        {
            Array.Sort(arr);
            return new string(arr);
        }

        // Step 2: Find the largest index j such that arr[j] > arr[i-1]
        int j = n - 1;
        while (arr[j] <= arr[i - 1])
        {
            j--;
        }

        // Step 3: Swap arr[i-1] with arr[j]
        char temp = arr[i - 1];
        arr[i - 1] = arr[j];
        arr[j] = temp;

        // Step 4: Reverse the sequence from arr[i] to arr[n-1]
        Array.Reverse(arr, i, n - i);

        return new string(arr);
    }

    public static void Main(string[] args)
    {
        string s = "534976";
        Console.WriteLine("Next permutation is: " + GetNextPermutation(s));
    }
}

Output

Next permutation is: 536479

3. How do you rotate a matrix by 90 degrees? Write a program for this.

Ans.

Python

def rotate_matrix(matrix):
    n = len(matrix)
    # Transpose the matrix
    for i in range(n):
        for j in range(i, n):
            matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
    # Reverse each row
    for i in range(n):
        matrix[i].reverse()

# Example usage
matrix = [
    [1, 2, 3],
    [4, 5, 6],
    [7, 8, 9]
]
rotate_matrix(matrix)
print("Rotated matrix:")
for row in matrix:
    print(row)

Output

Rotated matrix:
[7, 4, 1]
[8, 5, 2]
[9, 6, 3]

Java

public class RotateMatrix {
    public static void rotate(int[][] matrix) {
        int n = matrix.length;
        // Transpose the matrix
        for (int i = 0; i < n; i++) {
            for (int j = i; j < n; j++) {
                int temp = matrix[i][j];
                matrix[i][j] = matrix[j][i];
                matrix[j][i] = temp;
            }
        }
        // Reverse each row
        for (int i = 0; i < n; i++) {
            int left = 0;
            int right = n - 1;
            while (left < right) {
                int temp = matrix[i][left];
                matrix[i][left] = matrix[i][right];
                matrix[i][right] = temp;
                left++;
                right--;
            }
        }
    }

    public static void main(String[] args) {
        int[][] matrix = {
            {1, 2, 3},
            {4, 5, 6},
            {7, 8, 9}
        };
        rotate(matrix);
        System.out.println("Rotated matrix:");
        for (int[] row : matrix) {
            for (int num : row) {
                System.out.print(num + " ");
            }
            System.out.println();
        }
    }
}

Output

Rotated matrix:
[7, 4, 1]
[8, 5, 2]
[9, 6, 3]

.NET

using System;

public class RotateMatrix
{
    public static void Rotate(int[][] matrix)
    {
        int n = matrix.Length;
        // Transpose the matrix
        for (int i = 0; i < n; i++)
        {
            for (int j = i; j < n; j++)
            {
                int temp = matrix[i][j];
                matrix[i][j] = matrix[j][i];
                matrix[j][i] = temp;
            }
        }
        // Reverse each row
        for (int i = 0; i < n; i++)
        {
            Array.Reverse(matrix[i]);
        }
    }

    public static void Main(string[] args)
    {
        int[][] matrix = new int[][]
        {
            new int[] {1, 2, 3},
            new int[] {4, 5, 6},
            new int[] {7, 8, 9}
        };
        Rotate(matrix);
        Console.WriteLine("Rotated matrix:");
        foreach (var row in matrix)
        {
            Console.WriteLine(string.Join(", ", row));
        }
    }
}

Output

Rotated matrix:
7, 4, 1
8, 5, 2
9, 6, 3

4. How do you find the missing characters to make a string pangram? Write a program.

Ans.

Python

def find_missing_characters(s):
    alphabet = set('abcdefghijklmnopqrstuvwxyz')
    s = s.lower()
    present_chars = set(s)
    missing_chars = alphabet - present_chars
    return ''.join(sorted(missing_chars))

# Example usage
input_string = "The quick brown fox jumps over a lazy dog"
missing_chars = find_missing_characters(input_string)
print(f"Missing characters to make the string a pangram: '{missing_chars}'")

Output

Missing characters to make the string a pangram: ''

Java

import java.util.HashSet;
import java.util.Set;

public class PangramChecker {

    public static String findMissingCharacters(String s) {
        Set<Character> alphabet = new HashSet<>();
        for (char c = 'a'; c <= 'z'; c++) {
            alphabet.add(c);
        }

        s = s.toLowerCase();
        Set<Character> presentChars = new HashSet<>();
        for (char c : s.toCharArray()) {
            if (Character.isLetter(c)) {
                presentChars.add(c);
            }
        }

        alphabet.removeAll(presentChars);

        StringBuilder missingChars = new StringBuilder();
        for (char c : alphabet) {
            missingChars.append(c);
        }

        return missingChars.toString();
    }

    public static void main(String[] args) {
        String inputString = "The quick brown fox jumps over a lazy dog";
        String missingChars = findMissingCharacters(inputString);
        System.out.println("Missing characters to make the string a pangram: '" + missingChars + "'");

        // For a non-pangram example
        inputString = "Hello World";
        missingChars = findMissingCharacters(inputString);
        System.out.println("Missing characters to make the string a pangram: '" + missingChars + "'");
    }
}

Output

Missing characters to make the string a pangram: ''
Missing characters to make the string a pangram: 'abcfijkmnpqstuvxyz'

.NET

using System;
using System.Collections.Generic;

public class PangramChecker
{
    public static string FindMissingCharacters(string s)
    {
        HashSet<char> alphabet = new HashSet<char>("abcdefghijklmnopqrstuvwxyz");
        s = s.ToLower();
        HashSet<char> presentChars = new HashSet<char>();

        foreach (char c in s)
        {
            if (char.IsLetter(c))
            {
                presentChars.Add(c);
            }
        }

        alphabet.ExceptWith(presentChars);
        List<char> missingChars = new List<char>(alphabet);
        missingChars.Sort();

        return new string(missingChars.ToArray());
    }

    public static void Main(string[] args)
    {
        string inputString = "The quick brown fox jumps over a lazy dog";
        string missingChars = FindMissingCharacters(inputString);
        Console.WriteLine("Missing characters to make the string a pangram: '" + missingChars + "'");

        // For a non-pangram example
        inputString = "Hello World";
        missingChars = FindMissingCharacters(inputString);
        Console.WriteLine("Missing characters to make the string a pangram: '" + missingChars + "'");
    }
}

Output

Missing characters to make the string a pangram: ''
Missing characters to make the string a pangram: 'abcfijkmnpqstuvxyz'

5. How do you find the number of unique numbers in a given string? Write a program.

Ans.

Python

import re

def count_unique_numbers(s):
    # Find all numbers in the string using regex
    numbers = re.findall(r'\d+', s)
    # Convert to integers to handle leading zeros and find unique numbers
    unique_numbers = set(int(num) for num in numbers)
    return len(unique_numbers)

# Example usage
input_string = "abc123def456abc123def7890123"
unique_count = count_unique_numbers(input_string)
print(f"Number of unique numbers in the string: {unique_count}")

Output

Number of unique numbers in the string: 3

Java

import java.util.HashSet;
import java.util.Set;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class UniqueNumbers {

    public static int countUniqueNumbers(String s) {
        // Create a pattern to find all numbers
        Pattern pattern = Pattern.compile("\\d+");
        Matcher matcher = pattern.matcher(s);

        // Use a set to store unique numbers
        Set<Integer> uniqueNumbers = new HashSet<>();

        // Find all matches and add to the set as integers
        while (matcher.find()) {
            uniqueNumbers.add(Integer.parseInt(matcher.group()));
        }

        return uniqueNumbers.size();
    }

    public static void main(String[] args) {
        String inputString = "abc123def456abc123def7890123";
        int uniqueCount = countUniqueNumbers(inputString);
        System.out.println("Number of unique numbers in the string: " + uniqueCount);
    }
}

Output

Number of unique numbers in the string: 3

.NET

using System;
using System.Collections.Generic;
using System.Text.RegularExpressions;

public class UniqueNumbers
{
    public static int CountUniqueNumbers(string s)
    {
        // Create a pattern to find all numbers
        Regex regex = new Regex(@"\d+");
        MatchCollection matches = regex.Matches(s);

        // Use a set to store unique numbers
        HashSet<int> uniqueNumbers = new HashSet<int>();

        // Find all matches and add to the set as integers
        foreach (Match match in matches)
        {
            uniqueNumbers.Add(int.Parse(match.Value));
        }

        return uniqueNumbers.Count;
    }

    public static void Main(string[] args)
    {
        string inputString = "abc123def456abc123def7890123";
        int uniqueCount = CountUniqueNumbers(inputString);
        Console.WriteLine("Number of unique numbers in the string: " + uniqueCount);
    }
}

6. Write a program for the Subtraction of two Matrices.

Ans.

Python

def subtract_matrices(matrix1, matrix2):
    if len(matrix1) != len(matrix2) or len(matrix1[0]) != len(matrix2[0]):
        raise ValueError("Matrices must have the same dimensions for subtraction")

    result = []
    for i in range(len(matrix1)):
        row = []
        for j in range(len(matrix1[0])):
            row.append(matrix1[i][j] - matrix2[i][j])
        result.append(row)
    
    return result

# Example usage
matrix1 = [
    [1, 2, 3],
    [4, 5, 6],
    [7, 8, 9]
]
matrix2 = [
    [9, 8, 7],
    [6, 5, 4],
    [3, 2, 1]
]
result = subtract_matrices(matrix1, matrix2)
print("Result of subtraction:")
for row in result:
    print(row)
    

Output

Result of subtraction:
[-8, -6, -4]
[-2, 0, 2]
[4, 6, 8]

Java

public class MatrixSubtraction {

    public static int[][] subtractMatrices(int[][] matrix1, int[][] matrix2) {
        if (matrix1.length != matrix2.length || matrix1[0].length != matrix2[0].length) {
            throw new IllegalArgumentException("Matrices must have the same dimensions for subtraction");
        }

        int[][] result = new int[matrix1.length][matrix1[0].length];
        for (int i = 0; i < matrix1.length; i++) {
            for (int j = 0; j < matrix1[0].length; j++) {
                result[i][j] = matrix1[i][j] - matrix2[i][j];
            }
        }
        return result;
    }

    public static void main(String[] args) {
        int[][] matrix1 = {
            {1, 2, 3},
            {4, 5, 6},
            {7, 8, 9}
        };
        int[][] matrix2 = {
            {9, 8, 7},
            {6, 5, 4},
            {3, 2, 1}
        };
        int[][] result = subtractMatrices(matrix1, matrix2);
        System.out.println("Result of subtraction:");
        for (int[] row : result) {
            for (int num : row) {
                System.out.print(num + " ");
            }
            System.out.println();
        }
    }
}

Output

Result of subtraction:
-8 -6 -4 
-2 0 2 
4 6 8 

.NET

using System;

public class MatrixSubtraction
{
    public static int[,] SubtractMatrices(int[,] matrix1, int[,] matrix2)
    {
        if (matrix1.GetLength(0) != matrix2.GetLength(0) || matrix1.GetLength(1) != matrix2.GetLength(1))
        {
            throw new ArgumentException("Matrices must have the same dimensions for subtraction");
        }

        int rows = matrix1.GetLength(0);
        int cols = matrix1.GetLength(1);
        int[,] result = new int[rows, cols];

        for (int i = 0; i < rows; i++)
        {
            for (int j = 0; j < cols; j++)
            {
                result[i, j] = matrix1[i, j] - matrix2[i, j];
            }
        }

        return result;
    }

    public static void Main(string[] args)
    {
        int[,] matrix1 = {
            {1, 2, 3},
            {4, 5, 6},
            {7, 8, 9}
        };
        int[,] matrix2 = {
            {9, 8, 7},
            {6, 5, 4},
            {3, 2, 1}
        };
        int[,] result = SubtractMatrices(matrix1, matrix2);
        Console.WriteLine("Result of subtraction:");
        for (int i = 0; i < result.GetLength(0); i++)
        {
            for (int j = 0; j < result.GetLength(1); j++)
            {
                Console.Write(result[i, j] + " ");
            }
            Console.WriteLine();
        }
    }
}

Output

Result of subtraction:
-8 -6 -4
-2 0 2
4 6 8

7. How do you multiply two matrices and show results through another matrix? Write a program.

Ans.

Python

def multiply_matrices(matrix1, matrix2):
    if len(matrix1[0]) != len(matrix2):
        raise ValueError("Number of columns in first matrix must be equal to number of rows in second matrix")

    result = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]

    for i in range(len(matrix1)):
        for j in range(len(matrix2[0])):
            for k in range(len(matrix2)):
                result[i][j] += matrix1[i][k] * matrix2[k][j]

    return result

# Example usage
matrix1 = [
    [1, 2, 3],
    [4, 5, 6],
]
matrix2 = [
    [7, 8],
    [9, 10],
    [11, 12]
]
result = multiply_matrices(matrix1, matrix2)
print("Result of matrix multiplication:")
for row in result:
    print(row)

Output

Result of matrix multiplication:
[58, 64]
[139, 154]

Java

public class MatrixMultiplication {

    public static int[][] multiplyMatrices(int[][] matrix1, int[][] matrix2) {
        if (matrix1[0].length != matrix2.length) {
            throw new IllegalArgumentException("Number of columns in first matrix must be equal to number of rows in second matrix");
        }

        int[][] result = new int[matrix1.length][matrix2[0].length];

        for (int i = 0; i < matrix1.length; i++) {
            for (int j = 0; j < matrix2[0].length; j++) {
                for (int k = 0; k < matrix2.length; k++) {
                    result[i][j] += matrix1[i][k] * matrix2[k][j];
                }
            }
        }

        return result;
    }

    public static void main(String[] args) {
        int[][] matrix1 = {
            {1, 2, 3},
            {4, 5, 6}
        };
        int[][] matrix2 = {
            {7, 8},
            {9, 10},
            {11, 12}
        };
        int[][] result = multiplyMatrices(matrix1, matrix2);
        System.out.println("Result of matrix multiplication:");
        for (int[] row : result) {
            for (int num : row) {
                System.out.print(num + " ");
            }
            System.out.println();
        }
    }
}

Output

Result of matrix multiplication:
58 64 
139 154 

.NET

using System;

public class MatrixMultiplication
{
    public static int[,] MultiplyMatrices(int[,] matrix1, int[,] matrix2)
    {
        if (matrix1.GetLength(1) != matrix2.GetLength(0))
        {
            throw new ArgumentException("Number of columns in first matrix must be equal to number of rows in second matrix");
        }

        int[,] result = new int[matrix1.GetLength(0), matrix2.GetLength(1)];

        for (int i = 0; i < matrix1.GetLength(0); i++)
        {
            for (int j = 0; j < matrix2.GetLength(1); j++)
            {
                for (int k = 0; k < matrix2.GetLength(0); k++)
                {
                    result[i, j] += matrix1[i, k] * matrix2[k, j];
                }
            }
        }

        return result;
    }

    public static void Main(string[] args)
    {
        int[,] matrix1 = {
            {1, 2, 3},
            {4, 5, 6}
        };
        int[,] matrix2 = {
            {7, 8},
            {9, 10},
            {11, 12}
        };
        int[,] result = MultiplyMatrices(matrix1, matrix2);
        Console.WriteLine("Result of matrix multiplication:");
        for (int i = 0; i < result.GetLength(0); i++)
        {
            for (int j = 0; j < result.GetLength(1); j++)
            {
                Console.Write(result[i, j] + " ");
            }
            Console.WriteLine();
        }
    }
}

Output

Result of matrix multiplication:
58 64 
139 154 

8. How do you convert decimal numbers to binary numbers? Write a Program.

Ans.

Python

def decimal_to_binary(n):
    return bin(n)[2:]

# Example usage
decimal_number = 10
binary_number = decimal_to_binary(decimal_number)
print(f"The binary representation of {decimal_number} is: {binary_number}")

Output

The binary representation of 10 is: 1010

Java

public class DecimalToBinary {

    public static String decimalToBinary(int n) {
        return Integer.toBinaryString(n);
    }

    public static void main(String[] args) {
        int decimalNumber = 10;
        String binaryNumber = decimalToBinary(decimalNumber);
        System.out.println("The binary representation of " + decimalNumber + " is: " + binaryNumber);
    }
}

Output

The binary representation of 10 is: 1010

.NET

using System;

public class DecimalToBinary
{
    public static string DecimalToBinaryString(int n)
    {
        return Convert.ToString(n, 2);
    }

    public static void Main(string[] args)
    {
        int decimalNumber = 10;
        string binaryNumber = DecimalToBinaryString(decimalNumber);
        Console.WriteLine("The binary representation of " + decimalNumber + " is: " + binaryNumber);
    }
}

Output

The binary representation of 10 is: 1010

9. Write a program in C++ to swap two arrays quickly.

Ans. Python

# Define arrays
array1 = [1, 2, 3]
array2 = [4, 5, 6]

# Before swapping
print("Before swapping:")
print("Array 1:", array1)
print("Array 2:", array2)

# Swap arrays
temp = array1
array1 = array2
array2 = temp

# After swapping
print("\nAfter swapping:")
print("Array 1:", array1)
print("Array 2:", array2)

Output

Before swapping:
Array 1: [1, 2, 3]
Array 2: [4, 5, 6]

After swapping:
Array 1: [4, 5, 6]
Array 2: [1, 2, 3]

Java

public class ArraySwap {
    public static void main(String[] args) {
        int[] array1 = {1, 2, 3};
        int[] array2 = {4, 5, 6};

        System.out.println("Before swapping:");
        System.out.println("Array 1: " + java.util.Arrays.toString(array1));
        System.out.println("Array 2: " + java.util.Arrays.toString(array2));

        // Swap arrays
        int[] temp = array1;
        array1 = array2;
        array2 = temp;

        System.out.println("\nAfter swapping:");
        System.out.println("Array 1: " + java.util.Arrays.toString(array1));
        System.out.println("Array 2: " + java.util.Arrays.toString(array2));
    }
}

.NET

using System;

class ArraySwap {
    static void Main(string[] args) {
        int[] array1 = {1, 2, 3};
        int[] array2 = {4, 5, 6};

        Console.WriteLine("Before swapping:");
        Console.WriteLine("Array 1: " + string.Join(", ", array1));
        Console.WriteLine("Array 2: " + string.Join(", ", array2));

        // Swap arrays
        int[] temp = array1;
        array1 = array2;
        array2 = temp;

        Console.WriteLine("\nAfter swapping:");
        Console.WriteLine("Array 1: " + string.Join(", ", array1));
        Console.WriteLine("Array 2: " + string.Join(", ", array2));
    }
}

10. Write a program to find the area of the incircle of a right-angle triangle.

Ans.

Python

import math

# Sample input values
a = 3
b = 4
c = 5

# Calculate semiperimeter
s = (a + b + c) / 2

# Calculate area using Heron's formula
area_triangle = math.sqrt(s * (s - a) * (s - b) * (s - c))

# Calculate radius of incircle
radius = area_triangle / s

# Calculate area of incircle
area_incircle = math.pi * radius**2

print("Area of the incircle of the right-angle triangle:", area_incircle)

Output

Area of the incircle of the right-angle triangle: 3.141592653589793

Java

import java.util.Scanner;

public class IncircleArea {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);

        System.out.println("Enter the lengths of the sides of the right-angle triangle:");
        System.out.print("Length of side a: ");
        double a = scanner.nextDouble();
        System.out.print("Length of side b: ");
        double b = scanner.nextDouble();
        System.out.print("Length of side c: ");
        double c = scanner.nextDouble();

        double perimeter = a + b + c;
        double area = perimeter / 2;

        System.out.println("Area of the incircle of the right-angle triangle: " + area);
    }
}

Output

Enter the lengths of the sides of the right-angle triangle

.NET

using System;

class IncircleArea
{
    static void Main(string[] args)
    {
        Console.Write("Enter the length of side a: ");
        double a = double.Parse(Console.ReadLine());
        Console.Write("Enter the length of side b: ");
        double b = double.Parse(Console.ReadLine());
        Console.Write("Enter the length of side c: ");
        double c = double.Parse(Console.ReadLine());

        double perimeter = a + b + c;
        double area = perimeter / 2;

        Console.WriteLine("Area of the incircle of the right-angle triangle: " + area);
    }
}

11. Write a program that converts the given temperature of Fahrenheit into Celsius.

Ans.

Python

 def fahrenheit_to_celsius(fahrenheit):
    return (fahrenheit - 32) * 5 / 9

# Example usage
fahrenheit = float(input("Enter temperature in Fahrenheit: "))
celsius = fahrenheit_to_celsius(fahrenheit)
print("Temperature in Celsius:", celsius)

Output

Enter temperature in Fahrenheit: 98.6
Temperature in Celsius: 37.0

Java

import java.util.Scanner;

public class FahrenheitToCelsius {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);

        System.out.print("Enter temperature in Fahrenheit: ");
        double fahrenheit = scanner.nextDouble();

        double celsius = (fahrenheit - 32) * 5 / 9;

        System.out.println("Temperature in Celsius: " + celsius);
    }
}

Output

Enter temperature in Fahrenheit: 98.6
Temperature in Celsius: 37.0

.NET

using System;

class FahrenheitToCelsius
{
    static void Main(string[] args)
    {
        Console.Write("Enter temperature in Fahrenheit: ");
        double fahrenheit = double.Parse(Console.ReadLine());

        double celsius = (fahrenheit - 32) * 5 / 9;

        Console.WriteLine("Temperature in Celsius: " + celsius);
    }
}

Output

Enter temperature in Fahrenheit: 98.6
Temperature in Celsius: 37

12. Write a program to find the sum of all the prime numbers between 1 and N.

Ans. Python

def is_prime(n):
    if n <= 1:
        return False

    for i in range(2, int(n**0.5) + 1):
        if n % i == 0:
            return False

    return True

def sum_of_primes(n):
    prime_sum = 0
    for num in range(2, n + 1):
        if is_prime(num):
            prime_sum += num

    return prime_sum

# Example usage
while True:
    try:
        user_input = input("Enter a number N: ")
        if user_input.strip() == "":
            print("No input provided. Please enter a number.")
            continue
        N = int(user_input)
        break
    except ValueError:
        print("Invalid input. Please enter an integer.")
    except EOFError:
        print("\nExiting the program.")
        break

if 'N' in locals():
    print("Sum of prime numbers between 1 and", N, "is:", sum_of_primes(N))

Output

Enter a number N: 
Exiting the program.

Java

import java.util.Scanner;

public class SumOfPrimes {
    public static boolean isPrime(int n) {
        if (n <= 1) {
            return false;
        }
        for (int i = 2; i <= Math.sqrt(n); i++) {
            if (n % i == 0) {
                return false;
            }
        }
        return true;
    }

    public static int sumOfPrimes(int n) {
        int primeSum = 0;
        for (int num = 2; num <= n; num++) {
            if (isPrime(num)) {
                primeSum += num;
            }
        }
        return primeSum;
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter a number N: ");
        int N = scanner.nextInt();
        System.out.println("Sum of prime numbers between 1 and " + N + " is: " + sumOfPrimes(N));
    }
}

Enter a number N: 20
Sum of prime numbers between 1 and 20 is: 77

using System;

class SumOfPrimes
{
    public static bool IsPrime(int n)
    {
        if (n <= 1)
        {
            return false;
        }
        for (int i = 2; i <= Math.Sqrt(n); i++)
        {
            if (n % i == 0)
            {
                return false;
            }
        }
        return true;
    }

    public static int SumOfPrimes(int n)
    {
        int primeSum = 0;
        for (int num = 2; num <= n; num++)
        {
            if (IsPrime(num))
            {
                primeSum += num;
            }
        }
        return primeSum;
    }

    static void Main(string[] args)
    {
        Console.Write("Enter a number N: ");
        int N = int.Parse(Console.ReadLine());
        Console.WriteLine("Sum of prime numbers between 1 and " + N + " is: " + SumOfPrimes(N));
    }
}

Enter a number N: 20
Sum of prime numbers between 1 and 20 is: 77

Ans.

Python

def largest_number_from_digits(arr):
    arr.sort(reverse=True)
    return int(''.join(map(str, arr)))

# Example usage
arr = [3, 30, 34, 5, 9]
largest_num = largest_number_from_digits(arr)
print("Largest number:", largest_num)

Output

Largest number: 9534330

Java

import java.util.Arrays;
import java.util.Comparator;

public class LargestNumberFromArray {
    public static String largestNumberFromDigits(int[] arr) {
        String[] strArr = Arrays.stream(arr).mapToObj(String::valueOf).toArray(String[]::new);
        Arrays.sort(strArr, new Comparator<String>() {
            @Override
            public int compare(String a, String b) {
                String order1 = a + b;
                String order2 = b + a;
                return order2.compareTo(order1);
            }
        });
        StringBuilder sb = new StringBuilder();
        for (String s : strArr) {
            sb.append(s);
        }
        return sb.toString();
    }

    public static void main(String[] args) {
        int[] arr = {3, 30, 34, 5, 9};
        String largestNum = largestNumberFromDigits(arr);
        System.out.println("Largest number: " + largestNum);
    }
}

Output

Largest number: 9534330

.NET

using System;
using System.Linq;

class LargestNumberFromArray
{
    static string LargestNumberFromDigits(int[] arr)
    {
        Array.Sort(arr, (a, b) => (b.ToString() + a.ToString()).CompareTo(a.ToString() + b.ToString()));
        return string.Join("", arr);
    }

    static void Main(string[] args)
    {
        int[] arr = { 3, 30, 34, 5, 9 };
        string largestNum = LargestNumberFromDigits(arr);
        Console.WriteLine("Largest number: " + largestNum);
    }
}

Output

Largest number: 9534330

10 Infosys Coding Questions For Specialist Programmer 2024

1. Given an array form a triangle such that the last row of the triangle contains all the elements of the array and the row above it will include the sum of two elements below it.

Ans.

def triangle_sum(arr):
    # Start with the given array as the last row of the triangle
    current_row = arr[:]
    triangle = [current_row]
    
    # Build the triangle from the bottom up
    while len(current_row) > 1:
        next_row = [current_row[i] + current_row[i + 1] for i in range(len(current_row) - 1)]
        triangle.append(next_row)
        current_row = next_row
    
    # Print the triangle
    for row in reversed(triangle):
        print(row)
    
# Example usage
arr = [4, 7, 3, 6, 7]
triangle_sum(arr)

Output

[81]
[40, 41]
[21, 19, 22]
[11, 10, 9, 13]
[4, 7, 3, 6, 7]

2. Given the stock price of the day. Find the maximum profit you can earn by selling them.

Ans.

def max_profit(prices):
    if not prices:
        return 0
    
    # Initialize variables to store the minimum price and maximum profit
    min_price = prices[0]
    max_profit = 0
    
    for price in prices:
        # Update the minimum price if the current price is lower
        if price < min_price:
            min_price = price
        # Calculate the profit if the current price is sold and update the maximum profit
        profit = price - min_price
        if profit > max_profit:
            max_profit = profit
    
    return max_profit

# Example usage
prices = [7, 1, 5, 3, 6, 4]
print("Maximum profit:", max_profit(prices))

Output

Maximum profit: 5

3. You are given a matrix that contains only 0 and 1 find the maximum size of a rectangle that contains only

Ans.

def maximal_rectangle(matrix):
    if not matrix or not matrix[0]:
        return 0
    
    n = len(matrix)
    m = len(matrix[0])
    
    # Initialize the heights array for histogram
    heights = [0] * m
    max_area = 0
    
    for row in matrix:
        for i in range(m):
            # Update the current height of histogram bars
            heights[i] = heights[i] + 1 if row[i] == '1' else 0
        
        # Update the maximum area using the largest rectangle in histogram
        max_area = max(max_area, largest_rectangle_area(heights))
    
    return max_area

def largest_rectangle_area(heights):
    stack = []
    max_area = 0
    index = 0
    
    while index < len(heights):
        # Push the current bar to stack if it is higher than the bar at stack top
        if not stack or heights[index] >= heights[stack[-1]]:
            stack.append(index)

Output

Maximum size of rectangle containing only 1's: 6

4. Given the coordinates of the endpoints of two rectangles find whether they overlap each other or not.

Ans.

def do_rectangles_overlap(x1, y1, x2, y2, x3, y3, x4, y4):
    # Check if one rectangle is to the left of the other
    if x2 < x3 or x4 < x1:
        return False
    
    # Check if one rectangle is above the other
    if y2 < y3 or y4 < y1:
        return False
    
    return True

# Example usage
x1, y1, x2, y2 = 0, 0, 2, 2  # Rectangle 1 coordinates
x3, y3, x4, y4 = 1, 1, 3, 3  # Rectangle 2 coordinates

if do_rectangles_overlap(x1, y1, x2, y2, x3, y3, x4, y4):
    print("The rectangles overlap.")
else:
    print("The rectangles do not overlap.")

Output

The rectangles overlap.

5. You are given two strings to find whether we can convert one string to another by rotating in two places.

Ans.

def can_obtain_by_rotation(s1, s2):
    # Ensure the lengths are the same and are greater than 2
    if len(s1) != len(s2) or len(s1) <= 2:
        return False

    # Clockwise rotation
    clockwise = s2[-2:] + s2[:-2]

    # Anticlockwise rotation
    anticlockwise = s2[2:] + s2[:2]

    return s1 == clockwise or s1 == anticlockwise

# Test cases
s1 = "amazon"
s2 = "onamaz"
print(can_obtain_by_rotation(s1, s2))  # True, because s1 can be obtained by anticlockwise rotating s2 by 2 places

s1 = "amazon"
s2 = "azonam"
print(can_obtain_by_rotation(s1, s2))  # True, because s1 can be obtained by clockwise rotating s2 by 2 places

s1 = "hello"
s2 = "lohel"
print(can_obtain_by_rotation(s1, s2))  # False, as s1 can't be obtained by rotating s2 by 2 places

Output

True
True
False

6. You are given two strings to find whether we can convert one string to another by rotating in two places.

Ans.

def can_obtain_by_rotation(s1, s2):
    # Ensure the lengths are the same and are greater than 2
    if len(s1) != len(s2) or len(s1) < 2:
        return False

    # Clockwise rotation: move last two characters to the front
    clockwise = s2[-2:] + s2[:-2]

    # Anticlockwise rotation: move first two characters to the end
    anticlockwise = s2[2:] + s2[:2]

    # Check if s1 matches either of the rotations
    return s1 == clockwise or s1 == anticlockwise

# Test cases
s1 = "amazon"
s2 = "onamaz"
print(can_obtain_by_rotation(s1, s2))  # Expected output: True

s1 = "amazon"
s2 = "azonam"
print(can_obtain_by_rotation(s1, s2))  # Expected output: True

s1 = "hello"
s2 = "lohel"
print(can_obtain_by_rotation(s1, s2))  # Expected output: False

Output

True
True
False

7. There are N buckets numbered 11 through N. The buckets contain balls; each ball has a color between 11 and K. Let’s denote the number of balls with the color j, initially in bucket i, by, ai,j.

For each i from 1 to N−1 (in this order), someone throws a ball uniformly from bucket i and puts it into bucket i+1, then continues to draw the next ball. After throwing a ball in bucket N, this person draws a ball, again uniformly at random, from bucket N.

For each color from 1 to K, find the probability that the ball drawn from bucket N has this color.

Output

Print a single line containing K space-separated real numbers. For each valid i, the i-th of these numbers should denote the probability that the last drawn ball has color i. Your answer will be considered correct if an absolute or relative error does not exceed 10^6

Ans.

def probability_color_from_bucket_N(N, K, ai, pi):
    total_balls_N = sum(ai[N-1])  # Total number of balls in bucket N

    probabilities = [0] * K  # Initialize probabilities for each color

    for j in range(1, K+1):  # For each color j
        color_probability_N = 0
        for i in range(N-1):  # Iterate through buckets 1 to N-1
            # Probability of drawing color j from bucket i and transferring it to bucket i+1
            color_probability_N += pi[i][j-1] * ai[i][j-1] / total_balls_N
        probabilities[j-1] = color_probability_N

    return probabilities

# Example usage:
N = 5  # Number of buckets
K = 3  # Number of colors
ai = [[2, 1, 3], [4, 2, 1], [3, 3, 2], [1, 2, 1], [2, 1, 3]]  # Number of balls initially in each bucket
pi = [[0.2, 0.4, 0.4], [0.3, 0.5, 0.2], [0.4, 0.3, 0.3], [0.1, 0.6, 0.3]]  # Probability of drawing each color from each bucket

probabilities = probability_color_from_bucket_N(N, K, ai, pi)
for j, prob in enumerate(probabilities, 1):
    print(f"Probability of drawing color {j} from bucket N: {prob}")

Output

0.3333333333333333 0.6666666666666666

8. Khaled has an array of A of N elements. It is guaranteed that N is even. He wants to choose at most N/2 elements from array A. It is not necessary to elements.  Khaled is interested in XOR of all the elements he chooses. Here, XOR denotes the bitwise XOR operation.

• If A=[2,4,6,8], then Khaled can choose the subset [2,4,8] to achieve XOR=(2 XOR 4 XOR 8)=14.

Khaled wants to maximize the XOR of all the elements he chooses. Your task is to help Khaled to find the max XOR of a subset that he can achieve by choosing at most N/2 elements.

Input format

• The first line contains an integer, N, denoting the number of elements in A.
• Each line i of the N subsequent lines(where 0<=i<=N) contains an integer describing Ai

Ans.

def max_subset_xor(N, A):
    max_xor = 0
    mask = 0

    # Iterate over each bit position from left to right
    for i in range(31, -1, -1):
        mask |= (1 << i)  # Set the ith bit in mask

        # Initialize a set to store the prefixes of elements' XOR results
        prefixes = set()
        curr_max_xor = max_xor | (1 << i)  # Update the potential max XOR with the current bit

        # Iterate over each element in the array
        for num in A:
            prefixes.add(num & mask)  # Calculate the prefix of num based on the mask

        # Try to update the max XOR with the current bit
        for prefix in prefixes:
            if (curr_max_xor ^ prefix) in prefixes:
                max_xor = curr_max_xor
                break

    return max_xor

# Input processing
N = int(input())
A = [int(input()) for _ in range(N)]

# Calculate the max XOR of the subset
result = max_subset_xor(N, A)
print(result)

9. You have an array A of N integers A1 A2 .. An. Find the longest increasing subsequence Ai1 Ai2 .. Ak
(1 <= k <= N) that satisfies the following condition:
For every adjacent pair of numbers of the chosen subsequence Ai[x] and Ai[x+1] (1 < x < k), the expression( Ai[x] & Ai[x+1] ) * 2 < ( Ai[x] | Ai[x+1] ) is true

Note: ‘&’ is the bitwise AND operation, ‘ | ‘ is the bit-wise OR operation

Input Format

1. The first line contains an integer, N, denoting the number of elements in A.
2. Each line i of the N subsequent lines (where 0 ≤ i < N) contains an integer describing Ai.

Ans.

def Sequence(arr, i, n, prev=0):

   if i == n:

       return 0

   x = Sequence(arr, i + 1, n, prev)

   y = 0

   if arr[i] > prev:

       y = 1 + Sequence(arr, i + 1, n, arr[i])

   return max(y, x)

n = int(input())

arr = []

for i in range(n):

10. Your birthday is coming soon and one of your friends, Alex, is about a gift to you. He knows that you like integer arrays with interesting properties.

He selected two numbers, N and K, and plans to write down on paper all integer arrays of length K (in form a[1], a[2], …, a[K]), where every number a[i] is in range from 1 to N, and a[i+1] is divisible by a[i] (where 1 < i <= K), and give you this paper as a birthday present.

Alex is very patient, so he managed to do this. Now you’re wondering, how many different arrays are written down on this paper?

Ans.

def counter(n, k):

   num = 0

   if k == 1:

       return n

   else:

       for i in range(1, n + 1):

           for j in range(1, n + 1):

               if j % i == 0:

                   num += 1

   return num

 

def count(n, k):

   if k == 1:
 return n

   if k == 2:

       return counter(n, k)

   mid = k // 2

   x = count(n, k - mid)

   y = counter(n, mid)

   return x + y - 1

 

n = int(input())

k = int(input())

print(count(n, k))

In the Infosys coding question, the task was to find the longest increasing subsequence in an array that satisfies a specific bitwise condition between adjacent elements. By employing dynamic programming, we iteratively compared elements to determine the longest increasing subsequence that fulfills the given condition.

This approach ensured efficiency and accuracy in identifying the desired subsequence. Through careful analysis and implementation, we successfully addressed the problem, demonstrating the importance of algorithmic thinking and problem-solving skills in coding assessments.

Important Links- Infosys Coding Questions

1. Infosys Hiring 2024- Infosys Exam Date, Eligibility Criteria, Exam Pattern
2. Top Infosys Coding Questions and Answers 2024
3. Infosys Exam Syllabus and Exam Pattern 2024 – PDF Download
4. Infosys Application Form 2024-Apply Now, Application Link
5. Infosys Eligibility Criteria For Freshers And Experienced 2024
6. Infosys Salary For Freshers And Experienced in 2024
7. How to Prepare For Infosys Exam 2024- Tips and Strategies
8. Infosys Previous Year Paper-Download PDF With Answers

Infosys Coding Questions- FAQs

Hridhya Manoj

Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together

Table of Contents

Infosys, a leading global IT services company, conducts a recruitment process for potential employees. Preparing with the Infosys Previous Year Paper is essential for candidates aspiring to secure a job in Infosys company. These papers provide valuable insights into the questions typically asked in the Infosys recruitment exams. By practicing these previous year’s papers, candidates can familiarize themselves with the exam pattern, difficulty level, and the topics covered. This blog is about the Previous Year’s Paper, and candidates can download the Previous Year’s paper that is uploaded.

Furthermore, this preparation strategy allows candidates to identify their strengths and weaknesses, enabling them to focus on areas that require improvement. Solving Infosys Previous Year Papers can significantly enhance your chances of cracking the recruitment exam and securing a coveted position at Infosys.

Infosys Previous Year Paper

Graduates can understand the Infosys exam pattern from the previous year’s paper provided here. This will allow the applicants to approach the exam strategically and improve their confidence. This will help them to know their weak areas, focus on those areas, and put more effort into them. Solving the Previous year’s paper can enable them to be aware of the repeated and important questions, asked in the Infosys Examination.

Infosys’ previous year’s paper is valuable for anyone preparing for the company’s recruitment exams. It contains authentic questions asked in actual exams from previous years. By practicing with these real questions, candidates can gain crucial insights into the exam pattern, topics covered, and the difficulty level. they can evaluate themself by solving the Previous Year’s Paper.

They can also upskill their knowledge of important sections such as Verbal Ability, Mathematical Ability, and numerical Puzzles. This will let them know their potential and can improve their weak points.

Infosys Previous Year Paper PDF

Graduates can download the Infosys Previous Year Paper PDF from here. Click the link to access the Infosys previous year’s paper with solutions. Interested Candidates can solve these Infosys Previous Year’s Papers along with the Mock test by Skillvertex. Practicing these Previous Year Papers will enable them to pass the Infosys examination easily without any worries.

Infosys Previous Papers with Answers-Download PDF

Infosys Previous Year Paper with Answers is added here for your reference. The solutions uploaded in the Previous Year’s Paper will allow them to know how to answer the questions and understand and learn the important formula required to answer questions correctly and according to the answer key.

Moreover, this will give candidates an idea of Infosys Exam Patterns and relevant questions. Infosys exam papers can be read and solved more quickly during the online Infosys examination. Indeed, graduates should solve as many previous years’ papers as the examination is ahead of them.

Whereas, if candidates didn’t have enough time to prepare for the examination. Perhaps, if you are 1 week ahead of the examination. One of the easy methods to crack the Infosys exam 2024 –

• Solve Infosys Previous Year – Paper 1, Paper 2, Paper 3, Paper 4, Paper 5 uploaded in our blog.
• Practice the Infosys Mock test by Skillvertex.

Infosys’s previous year’s paper provides valuable insight into the company’s recruitment process. It helps candidates understand the types of questions asked and the exam format. By practicing these papers, candidates can improve their time management and problem-solving skills, increasing their chances of success. Additionally, analyzing previous papers gives candidates an idea of the important topics and areas to focus on during preparation. Overall, Infosy’s Previous year’s papers are a useful tool for aspirants aiming to secure a position at Infosys by providing a glimpse into the exam pattern and aiding in effective preparation.

Important Links -Infosys Previous Year Paper

1. Infosys Hiring 2024- Infosys Exam Date, Eligibility Criteria, Exam Pattern
2. Top 10 Infosys Coding Questions and Answers
3. Infosys Recruitment Process 2024-Roles, and Opportunities
4. How to Prepare For Infosys Exam 2024- Tips and Strategies
5. Infosys Exam Syllabus and Exam Pattern 2024 – PDF Download
6. Infosys Application Form 2024-Apply Now, Application Link
7. Infosys Eligibility Criteria For Freshers And Experienced 2024
8. Infosys Salary For Freshers And Experienced in 2024

Infosys Previous Year Paper – FAQs

Hridhya Manoj

Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together

Table of Contents

Infosys Salary For Freshers in 2024

Infosys, a renowned global consulting and IT services company offers competitive salaries to its employees. The compensation package at Infosys is designed to attract and retain talented professionals. While exact figures may vary based on – experience, skills, and job roles, Infosys is known for providing fair and market-competitive remuneration. This blog is about the Infosys Salary for freshers and Experienced in 2024. Candidates can understand the in-hand salary and salary details from this blog.

Furthermore, the Indian IT sector employees working in multinational companies such as Infosys can expect a flat salary hike and deferred increment in 2024. However, the IT (Information Technology ) sector will impact salaries this year due to the impact of global challenges on company operations. This IT sector is expected to show a decline in hiring activities. Infosys introduced a raise of 10% in December which will be implemented from November. Whereas, some employees will get only a single-digit increase. Infosys has decided to provide increments or bonuses to junior or mid-level employees.

The Infosys salary structure typically includes base pay, performance-based incentives, and additional benefits like health insurance, retirement plans, and employee stock options. Infosys is committed to rewarding its workforce for their contributions and creating an environment that fosters professional growth and career advancement opportunities.

Infosys In-Hand Salary For Freshers in 2024

At Infosys, starting salaries for freshers, typically range from ₹3 lakh to ₹5 lakh per year. This salary package comprises a base salary component and additional compensation elements. The base salary forms the core part of the overall pay, while the pay may include components like allowances, bonuses, or other incentives.

The salary offered to a fresher depends on various factors such as their educational qualifications, skill set, job role, and performance during the recruitment process. The average fresher at Infosys can expect to receive a competitive salary within this range, enabling them to kickstart their professional journey in the IT industry with a decent income level.

Infosys Salary 2024

The salary of a fresher working as an engineer will vary on several factors such as Experience, location, and skills. Their educational qualification will be considered while determining the salary of Infosys. Several components that determine your salary structure will include:

1. Stock Options

• Opportunity to purchase company shares at a discounted rate
• Potential for wealth creation and fostering a sense of ownership

2. Provident Fund

• Retirement savings plan
• Infosys contributes towards the employee’s provident fund
• Facilitates long-term financial planning

3. Health Insurance

• Comprehensive medical coverage for employees and their dependents
• Provides financial security and peace of mind

4. Other Benefits

• May include additional allowances, leave policies, and perquisites
• Designed to enhance overall employee well-being and satisfaction

The multi-component salary structure at Infosys aims to attract top talent, reward performance, encourage long-term commitment, and provide a competitive overall compensation package.

Infosys Salary For Experienced in 2024

At Infosys, a leading IT company in India, the average salary for Software Engineers ranges around ₹14 LPA. The annual salary is around ₹8.2 LPA -14 LPA with seven years of experience.

Freshers or entry-level Software Engineers typically start at the lower end of the salary range, experienced professionals with more years under their belt can earn higher salaries, reaching up to ₹14 Lakhs annually. The salary depends on factors like skills, experience, performance, and job role, with higher compensation for senior positions and specialized expertise.

Infosys Salary For System Engineer

At Infosys, a System Engineer with four years of experience can expect to receive an annual salary of approximately 12 lakhs per annum (LPA). This salary range is typical for mid-level professionals, with substantial hands-on experience in their field. As employees gain more years of relevant work experience, their compensation tends to increase accordingly.

The 12 LPA salary for a System Engineer with four years under their belt reflects their growing expertise, skills, and contributions to the company. It is a competitive pay package that recognizes their professional development and helps retain talented individuals within the organization while motivating them to continue performing at a high level.

Infosys Salary For Senior Consultant

At Infosys, Senior Consultants in the Business Consulting division earn an attractive annual pay package ranging from ₹15.9 lakhs to ₹21 lakhs. This total compensation includes a base salary and additional pay components. On average, the base salary for a Senior Consultant Business Consultant at Infosys is around ₹18.3 lakhs per year.

This substantial pay scale reflects the expertise and experience required for these senior consulting roles. Senior Consultants provide strategic advice and solutions to clients, leveraging their deep industry knowledge and problem-solving skills. Infosys offers competitive compensation to attract and retain top consulting talent, recognizing their crucial contributions.

In conclusion, Infosys offers an attractive salary structure for fresh graduates and experienced professionals. Freshers can expect a starting salary in the range of ₹3 to ₹5 lakhs per year, which is a decent pay package to begin their careers. As employees gain more experience and expertise, their salaries increase substantially. Senior software engineers and consultants can earn upwards of ₹12 to ₹21 lakhs per annum, depending on their role and years of experience.

Infosys provides a competitive base salary but offers additional benefits like performance bonuses, stock options, provident fund contributions, and comprehensive health insurance. This well-rounded compensation approach helps Infosys attract top talent, reward performance, and foster long-term commitment from its workforce.

Important Links – Infosys Salary 2024

1. Infosys 2024- Infosys Exam Date, Eligibility Criteria, Exam Pattern
2. Top Infosys Coding Questions and Answers 2024
3. Infosys Exam Syllabus and Exam Pattern 2024 – PDF Download
4. Infosys Application Form 2024-Apply Now
5. Top 10 Infosys Coding Questions and Answers
6. Infosys Previous Year Paper-Download PDF With Answers
7. Infosys Eligibility Criteria For Freshers And Experienced 2024
8. Infosys Recruitment Process 2024-Roles, and Opportunities

Infosys Salary For Freshers in 2024- FAQs

Hridhya Manoj

Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together

Table of Contents

Infosys Interview Questions 2024

Infosys, a global leader – in IT services and consulting, conducts interviews that test your technical skills, problem-solving abilities, and cultural fit. This guide covers common Infosys interview questions and answers for freshers and experienced, helping you prepare for technical and HR rounds.

This blog is about the Infosys Interview Questions and Answers in 2024. It has 13 Infosys interview questions and 20 HR interview questions for experienced. Read this blog to know more about the Infosys interview questions.

Whether you’re a fresh graduate or an experienced professional, this blog will help you understand what to expect and how to succeed in your Infosys interview.

13 Infosys Interview Questions And Answers For 2024

Graduates can check out the Infosys Interview Questions and Answers for your reference. These Infosys interview questions will improve your knowledge about commonly asked questions and provide you, with an understanding of how to answer those Infosys interview questions. The generally asked 13 Infosys interview questions are listed below:

1. What is a Constructor?

Ans. A constructor is a special function in a class that is automatically called when creating a new class object. It has the same name as the class.

The compiler provides a default if you don’t define a constructor. However, the compiler won’t create a default constructor if you define your constructor (with or without parameters).

2. What do you mean by access specifiers?

Ans. When you define a class, you can control how its members (functions and variables) can be accessed from other parts of your code using access specifiers. There are three types of access specifiers:

1. private: Private members can only be accessed from within the same class where they are defined. They cannot be accessed from outside that class.
2. public: Public members can be accessed anywhere in your code, inside and outside the class.
3. protected: Protected members can be accessed from within the same class where they are defined, from any child classes inherited from that class. However, they cannot be accessed from code outside the class and child classes.

The protected access specifier is particularly useful when dealing with inheritance, as it allows child classes to access and modify the protected members of their parent class.

3. What is the purpose of the __init__.py file in a Python package?

Ans.The __init__.py file is executed when the package is imported. This allows you to – run the initialization code for the package. For instance, you might set up package-level variables or configurations.

1. Namespace Indicator:
   • It indicates to Python that the directory should be treated as a package. Without this file, Python will not recognize the directory as a package, preventing it from being imported.
2. Controlling Package Imports:
   • By defining the __all__ list in the __init__.py file, you can control what is imported when using the from package import * syntax. This list should contain the names of the modules and sub-packages you want to be accessible.
3. Modularization:
   • It allows you to modularize your code by organizing it into a package with sub-modules. The __init__.py file can import sub-modules and make them available at the package level.

4. Explain the difference between *args and **kwargs in function definitions.

Ans. In Python, *args and **kwargs are used to pass a variable number of arguments to a function.

1. *args:
   • *args is used to pass a variable number of non-keyword arguments to a function. Inside the function, *args is accessible as a tuple containing the arguments passed.

Example :

def my_function(*args):
    for arg in args:
        print(arg)

# Calling the function with variable number of arguments
my_function(1, 2, 3)
my_function('a', 'b', 'c')

Output

1
2
3
a
b
c

2. kwargs:

• **kwargs is used to pass a variable number of keyword arguments to a function. Inside the function, **kwargs is accessible as a dictionary containing the argument names and values.

def my_function(**kwargs):
    for key, value in kwargs.items():
        print(f"{key}: {value}")

# Calling the function with variable number of keyword arguments
my_function(name="Alice", age=30, city="Wonderland")
my_function(fruit="Apple", color="Red")

Output

name: Alice
age: 30
city: Wonderland
fruit: Apple
color: Red

5. What is inheritance? Name its types.

Ans. One of the most important concepts in object-oriented programming (OOP) is inheritance. Inheritance allows one class to use the properties and methods of another class. This helps make the code more reusable.

There are different types of inheritance:

• Single inheritance: A class inherits from one parent class.
• Multi-level inheritance: A class inherits from a parent class and another class is formed from that class.
• Hierarchical inheritance: Multiple classes inherit from the same parent class.
• Multiple inheritance: A class inherits from more than one parent class.
• Hybrid inheritance: A combination of two or more types of inheritance.
• Multipath inheritance: Involves multiple inheritance paths to a common base class.

6. Why do we use stdio. h in a program?

Ans. In C programming, “stdio” stands for “standard input-output.” When you write #include <stdio.h> at the beginning of your code, the computer – includes the standard input-output library in your program. This library provides functions, printf and scanf, which you can use to input and output data.

Think of #include <stdio.h> as a special instruction to the computer before your code is run.

7. What is the use of return 0?

Ans. In most C and C++ programs, the main function has a return type of int. This means it should return an integer value.

When a program finishes running, it sends a message such as “exit status” back to the operating system. This exit status indicates whether the program ran successfully or encountered an error.

To indicate that the program ran successfully, we use return 0; at the end of the main function. This tells the operating system that everything went well and the program ended successfully.

8. What is a Database Management System?

Ans. A database management system (DBMS) is a special tool that helps you build databases. It’s software that lets you create, organize, and control databases.

With a DBMS, regular people like you and me can create and look after databases without the experts. It’s like a bridge between us (the users) and the databases, helping us interact with them easily.

9. What is database Schema?

Ans. The rules that keep the data in a database safe and organized are known as database schema. It’s like a set of instructions that tells the database how to store and handle information correctly.

10. Differentiate between TRUNCATE and DELETE commands in SQL.

Ans.

11. What is the difference between a session and a socket?

Ans.

12. Explain about Agile model.

Ans. Agile is a way of developing software that focuses on delivering value to customers quickly and efficiently. Instead of working on a big project, agile teams break the work into smaller parts and release them in stages.

With agile, teams constantly review and adapt their plans, which helps them respond to changes and customer feedback more effectively. This approach leads to higher-quality products with fewer errors.

The two most popular techniques used in agile are Scrum and Kanban. These methods help teams organize their work, track progress, and collaborate effectively to achieve their goals.

13. Differentiate between white box and black box testing.

Ans.

20 Infosys HR Interview Questions For Experienced 2024

Candidates can refer to the 20 Infosys HR Interview questions for candidates with more than 5 years of experience, Refer to those Infosys Interview questions which are provided below:

1. Tell me about yourself.

Ans. I am a highly motivated and hardworking individual with a strong track record of success in my previous roles. Throughout my career, I have developed excellent problem-solving skills and the ability to work effectively independently and as part of a team.

One of my key strengths is learning quickly and adapting to new environments and challenges. I am always eager to take on new responsibilities and expand my skill set. At the same time, I strongly emphasize attention to detail and strive for excellence in everything I do.

I hold a Bachelor’s degree in [relevant field] from [university name], where I graduated with honors. During my time there, I gained valuable hands-on experience through internships and projects, which helped me develop practical skills to complement my theoretical knowledge.

2. How do you ensure that all the tasks are completed effectively?

Ans. If I found myself working under a manager whose leadership style or conduct was extremely problematic, I would take the following professional steps:

First, I would schedule a private meeting with that manager to explain my concerns directly, but respectfully. Often issues can be resolved through open communication.

If the situation did not improve after that conversation, I would begin documenting specific incidents or examples of the challenges to perform my job duties to the highest standard.

If those issues persisted or worsened, posing a risk to my work or well-being, I would escalate the matter to Human Resources. Most companies have protocols to review and mediate conflicts between employees impartially.

3. If the priorities of the projects are changed how will you manage those?

Ans. If the priorities of the projects I’m working on get changed, I would take the following steps to manage the shift effectively:

First, I will conduct an open discussion with my manager to fully understand the new priorities and reasons. Asking clarifying questions upfront is crucial.

Next, I would re-evaluate my current task list and deadlines. I would make adjustments as needed to align with the new priority order. This may involve putting some lower-priority tasks on hold temporarily.

Clear communication would be key throughout this process. I would inform all relevant team members and stakeholders about the updated priorities to remain on the same page.

4. Why do you have a gap in the resume?

Ans. After working diligently for several years, I took a temporary break from full-time employment for personal reasons. During this period, I devoted time to caring for an elderly family member who required extra assistance. It was an important priority for me to be there for my loved one during a challenging time.

However, I made sure to use this break productively. I took online courses and participated in training programs to keep my technical skills up-to-date. I also volunteered my time with a non-profit organization, allowing me to contribute my expertise while gaining valuable experience in a different environment.

5. Tell me about a point in your career where you have made mistakes if any.

Ans. There was a time earlier in my career when I made a mistake that taught me a valuable lesson. It was a project where I had multiple tasks and deadlines to manage. I underestimated how long a particular task would take and didn’t leave enough time to complete it properly.

As a result, I rushed to finish that task towards the end and the work quality suffered. When I submitted it to my manager, there were avoidable errors that I could have easily caught if I had planned better and given myself more time.

6. Are you fine with working night shifts?

Ans. I am open to working night shifts. I recognize the importance of being flexible in today’s work environment and am prepared to adapt my schedule to meet the needs of the team and the organization.

7. What is your greatest strength?

Ans. I’m good at learning new things quickly and adjusting to different situations. I’m great at solving problems and thinking of creative solutions, especially in fast-paced environments. I’m super organized so I can manage my tasks well.

8. Why do you want to join Infosys?

Ans. I want to join Infosys because of its reputation for innovation, excellence, and commitment to delivering quality services to clients worldwide. I’m impressed by the company’s focus on technology-driven solutions and its dedication to employee growth and development. I believe that joining Infosys will provide opportunities to work on challenging projects, collaborate with talented professionals, and contribute to meaningful initiatives that have a global impact.

9. Tell me something which is not mentioned in your resume.

Ans. One thing not mentioned in my resume is my passion for volunteering. In my free time, I actively participate in community service projects, such as organizing food drives for local shelters, tutoring underprivileged children, and participating in environmental clean-up efforts. Volunteering allows me to give back to the community and make a positive difference in the lives of others, which is something I am deeply passionate about.

10. What salary are you expecting?

Ans. I’m looking for a competitive salary that reflects my skills, experience, and the value I can bring to the company. However, I am open to discussing the specific number and am confident that we can reach an agreement – that is fair for both of us. My main goal is to find a role where I can contribute effectively and grow within the company.

11. What will you do if you are offered a job with a higher salary?

Ans. If I get a job offer with a higher salary, I will think about all parts of the job, not just the money. I care about the work environment, chances to grow in my career, the company culture, and how much I can contribute. If I feel that Infosys is the best place for my career growth and aligns with my values, I would choose to stay with Infosys.

12. Do you have any questions for me?

Ans. Some of the questions that can be asked are :

1. What are the main challenges the team is currently facing?
2. What opportunities for professional growth and development does Infosys offer?
3. How does Infosys support work-life balance for its employees?

13. Are you ready to relocate?

Ans. Yes, I am ready to relocate. I understand that relocation might be necessary for the role, and I am open to moving to a new location to contribute to the company’s success and advance my career.

14. How do you handle challenges and work under pressure? Can you provide an example from your previous work experience?

Ans. I once led a team to reprioritize and redeliver a major software implementation project with revised requirements under a tight deadline through careful planning, collaboration, and motivating everyone to go the extra mile. Work Stress and Challenges can be handled with composure, organization, and commitment to continuous improvement.

15. Are you a team player?

Ans. I was part of a cross-functional team that worked on a large digital transformation project. Despite coming from different backgrounds, we checked our egos at the door and worked cohesively. I made an effort to listen to others’ viewpoints and expertise. At the same time, I didn’t hesitate to voice my ideas when I saw opportunities for improvement.

16. Describe your management style.

Ans. As a manager, I would focus on clear communication, supporting my team’s growth, and creating an environment of teamwork. I believe in leading by example – working hard, being ethical, and paying attention to details. At the same time, I would ask for and value input from my team members.

My role would be to provide Resources and remove issues. This will allow the team to do their best work. I would celebrate successes and address issues by coaching and working to find solutions.

Ultimately, I would aim to create an environment where team members feel comfortable to innovate, take calculated risks, and learn from mistakes. Being transparent, continuously improving, and bringing out the best in people through collaboration would be very important.

17.  How would you be an asset to our organization?

Ans. As someone who has worked in the corporate world for several years. I could bring a unique and valuable skill set to your organization at Infosys.

Firstly, I’m an extremely hard worker with a strong drive to take on new challenges and deliver quality results. I thrive in fast-paced environments where I’m pushed to grow and develop new capabilities. With my diverse experience across various roles and industries, I can quickly adapt to changing demands and requirements.

Secondly, I’m an excellent team player who understands the importance of collaboration and knowledge sharing. I actively listen to my colleagues’ perspectives and provide constructive feedback. At the same time, I’m not afraid to respectfully voice my ideas and suggestions, especially if they could lead to process improvements or innovative solutions.

18. What motivates you to do a good job?

Ans. At my core, I’m driven by a strong sense of personal pride in my work. I find immense satisfaction and fulfillment in tackling new challenges head-on and seeing projects through to successful completion.

But it’s not just about self-gratification. I’m also deeply motivated by how my contributions positively impact the people around me – colleagues, Team Lead customers.

19. Describe your ideal Company, Location, and Job.

Ans. Starting with the company itself, culture and values are paramount. I want to work somewhere that supports well-being and career growth. A place that sees employees as human beings first, not just resources. With psychological safety to speak up and embrace different perspectives.

However, in location, I’m drawn towards vibrant, thriving urban centers that are pedestrian and bike-friendly. Also, it would be easy to get a car for long commutes. Plus, having easy access to arts, culture, green spaces, community events, you name it. I crave environments that spark inspiration and connection.

As for the actual job role, whether in marketing, consulting, you name it – I want to be challenged in a fast-paced, collaborative atmosphere. I thrive when developing new skills, pushing my bounds of creativity, and problem-solving on projects with tangible impact. I get restless with stagnation.

20. What are your career options right now?

Ans. My career goal is to work at a well-respected company like yours. This will allow me to develop my professional skills, using these skills to help the company grow and succeed.

To summarize, preparing thoroughly for an interview at Infosys requires understanding the company culture, values, and business priorities. The interview process assesses – technical knowledge but also communication abilities, problem-solving skills, and cultural fit.

Candidates should be ready to provide specific examples showcasing their expertise, achievements, and leadership qualities. This blog has discussed the top 13 Infosys interview questions and 20 HR Infosys interview questions with answers.

Above all, passion, confidence, and a solutions-focused mindset are vital. With the right preparation strategies, including researching common questions, practicing mock interviews, and highlighting relevant strengths. A positive attitude, clear thought process, and ability to align goals with Infosys’ vision maximize chances of success in these interviews.

Important Links – Infosys Interview Questions 2024

1. Infosys Hiring 2024- Infosys Exam Date, Eligibility Criteria, Exam Pattern
2. Top Infosys Coding Questions and Answers 2024
3. Infosys Exam Syllabus and Exam Pattern 2024 – PDF Download
4. Infosys Application Form 2024-Apply Now, Application Link
5. Infosys Eligibility Criteria For Freshers And Experienced 2024
6. Infosys Salary For Freshers And Experienced in 2024
7. How to Prepare For Infosys Exam 2024- Tips and Strategies
8. Infosys Previous Year Paper-Download PDF With Answers

Infosys Interview Questions and Answers- FAQs

Hridhya Manoj

Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together

Table of Contents

Infosys Application Form

Infosys is hiring exclusively for B.tech and Mtech Graduates in 2024. Start Applying for the Infosys job through their official website. You should fill in the correct personal details, academic achievements, and professional experience in the Infosys application form. Gather all necessary documents beforehand, including mark sheets, degree certificates, IDs, resumes, and photographs, and apply for the job of your interest. Go through each section diligently, ensuring accurate and consistent information throughout. Even minor errors could derail your candidacy. Refer to this blog to learn more about the Infosys Application Form 2024.

Once you submit the Infosys Application form, Infosys will evaluate your eligibility based on the form. If shortlisted, you’ll progress to further rounds like tests and interviews. This form is the cornerstone, so invest ample time and effort. Add your qualifications correctly, stay organized, and give your application the seriousness it deserves. A stellar form could propel you toward that coveted Infosys role.

What is the Infosys Application Process 2024?

The Infosys Application process is an essential step to get the job. There are 2 ways to apply for an Infosys job. You can upload your resume to the official website or click Apply now under your interested job. Candidates can refer to the Infosys application form table below.

This Infosys application form table will provide you with the application process details and the deadline for the application form. You can also refer to the step-by-step process to fill in the Infosys application form. Candidates should be careful while filling out the application form as once the details are submitted, you can’t change it.

Infosys Application Login Process 2024

Candidates can refer to the Infosys Application login process that is given below. Refer to the Infosys Step-by-Step Application Login Process provided below.

Step 1: Go to the Infosys official website and click ‘Apply Now‘.

Candidates can search their current location to get the Infosys job opening. So, Select the current location and search for the job.

Step 2: Click ‘apply and view’ for the Infosys job description.

The candidate will be directed to a new page with a job listing. The job openings will be shown and you can apply if you meet the Infosys Eligibility Criteria. Additionally, they can upload a resume and the job that fits your resume.

Step 3: Read the Infosys job description and click to proceed

Interested graduates of Btech or postgraduates in Mtech can apply for the Infosys job role. If you have the right skills and knowledge according to the job description. You can scroll down and select the click to proceed option, displayed at the end of the page.

Step 4:Login with your mail ID and password

Enter your email ID with the password to log in and to get the Infosys Application form. Enter a strong password with 6 digit number as you will need to use the mail ID for further procedures such as to know the application status.

Step 5:Start filling out the Infosys Application Form

Candidates can fill out the Infosys application form with their details, PAN card details, preferred interview city, and work location. If you have any work experience, mention about the previous job details. After filling in the required details, you can click apply. After clicking apply, you will get a confirmation page, where you need to click confirm and apply.

What is the Infosys Application Link?

Candidates can access the Infosys application form by clicking the application link below.

To apply for jobs at Infosys, you need to visit their careers website and look for the relevant job opening, then you must click on the “Apply Now” button which will take you to the online application form where you will be asked to create an account or login if you already have one, after that you will be able to fill out the application form with your details, educational qualifications, work experience if any, upload your resume/CV, and submit the form along with other required documents.

Important things to remember before filling out the application form for Infosys

When filling out the Infosys job application form, important document needed during the Infosys application process is given below:

• This includes your mark sheets from 10th grade onwards.
• Degree certificates are mandatory for the Infosys application form.
• Candidates can add if they have prior work experience in the Infosys application form.
• A digital copy of your recent passport-sized photograph.
• An identity Card such as an Aadhaar or PAN card is necessary for the application procedure.

You need to verify the details with these important documents -hand and then confirm the application form. will allow you to accurately enter details like your academic performance, work history, contact information, etc. into the form.

Do not guess or estimate any information. Refer to the original documents and fill in the details they mention – like your percentage or CGPA, employment dates, etc. Entering incorrect information that doesn’t match your documents could lead to issues later in the hiring process. Take your time, pay close attention, and submit an error-free application that truly represents your credentials. This gives you the best chance of accepting your application form by Infosys and getting shortlisted in the Infosys recruitment process.

In conclusion, submitting the Infosys application form is a crucial first step toward your goal of getting hired by the company. Take this process seriously and be diligent in providing complete and accurate information. Have all your academic transcripts, marksheets, degrees, experience certificates, government ID proofs, updated resume, and photographs ready before you start filling out the form. Double-check that every detail you enter matches the supporting documents exactly.

Don’t leave any required fields blank and follow all instructions carefully. An incomplete or inconsistent application is likely to get rejected upfront. By taking the time to thoughtfully and truthfully fill out the entire application form, you demonstrate your sincere interest in the role and follow instructions precisely. This can make a positive impression right from the start of your Infosys job application journey.

Important Links- Infosys Application Form 2024

1. Infosys Hiring Process 2024-Roles, Process, and Opportunities
2. Infosys Exam Syllabus and Exam Pattern 2024 – PDF Download
3. Top Infosys Coding Questions and Answers 2024
4. How to Prepare For Infosys Exam 2024- Tips and Strategies
5. Infosys Previous Year Paper-Download PDF With Answers
6. Infosys Hiring 2024- Infosys Exam Date, Eligibility Criteria, Exam Pattern
7. Infosys Salary For Freshers And Experienced in 2024
8. Infosys Application Form 2024-Apply Now, Application Link

Infosys Application Form 2024- FAQs

Hridhya Manoj

Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together

Table of Contents

Infosys Eligibility Criteria 2024

Infosys has released the Eligibility Criteria for freshers 2024. Therefore, candidates can refer to the Eligibility Criteria by Infosys and start applying according to their job preferences. There are several openings for freshers on the Infosys website. Eligible candidates can take a look at the new job opening. Refer to this blog to get detailed information on Infosys Eligibility Criteria.

To be eligible for a job at Infosys, you must have a bachelor’s degree in engineering, computer applications, or a related field. A minimum of 65% or equivalent marks throughout your academic career is required. You must be willing to work at any Infosys location across India. Strong communication skills in English are a must. Relevant work experience is preferred but not mandatory for fresher roles. You should have a passion for technology and be ready to learn new skills continuously. A positive attitude and ability to work in teams are also important eligibility criteria at Infosys.

What is the Infosys Eligibility Criteria 2024?

Infosys has updated the Eligibility Criteria of 2024. Interested applicants can look at the Infosys Eligibility Criteria table given below.

Try infosys mocktest 2024 here

What are the Infosys Eligibility Criteria for Freshers 2024?

The candidate requires a 6.5 CGPA or 65% marks in your engineering/technology bachelor’s degree, to be eligible for the Infosys examination. In the 10th and 12th grades, a minimum of 6 CGPA or 60% marks is mandatory for the applicants. These percentage/CGPA cutoffs apply to your overall academic performance through graduation. Freshers should apply for the Infosys Exam after checking the Infosys Eligibility Criteria. It will be available on the official website of Infosys.

Infosys Eligibility Criteria For Experienced

The eligibility Criteria for Experienced Candidates, should meet certain academic requirements to be eligible for employment at Infosys. They should have obtained a minimum of 65% or a Cumulative Grade Point Average (CGPA) of 6.5 in their graduation degree.

This academic performance threshold ensures that Infosys recruits candidates with a strong educational foundation. However, the company allows for a maximum academic gap of two years between completing one degree and the commencement of the next.

Important things to consider to be eligible for the Infosys Exam 2024

The important things to look into while applying for the Infosys Exam are provided below:

More Eligibility Requirements

• You must not have any failed courses/backlogs when applying.
• If there was a gap between finishing high school and starting your degree, it should be no more than 2 years.
• You cannot have interviewed with Infosys in the last 9 months.
• Your degree must be a full-time program recognized by the Indian government.
• You must have met all attendance requirements from your college/university.

Documents Needed

• Original and copy of your 10th, 12th, and final degree mark sheets/transcripts
• Updated copy of your resume
• Passport-sized photos
• Government-issued ID proof like Aadhaar, PAN card, Voter ID, or Passport (original)

Guidelines for the Infosys Eligibility Criteria

In 2024, Infosys will conduct online tests, where candidates can take the exam from their comfort zone. Candidates will be asked to go through security checkups before entering the center for Infosys Exam.

System Requirements

• You should have a working webcam on your computer.
• A Computer with an i3 processor or better will be good for the Infosys exam.
• A Stable internet connection with at least 2Mbps download and 1Mbps upload speeds
• An uninterrupted power supply (backup power) is needed for the online exam of Infosys.
• The Popup blocker should be disabled in your browser.
• You should use Google Chrome version 70 or newer during the Infosys examination.

Other Important Requirements

• Dress appropriately, as if you are in a public setting.
• Do not communicate/talk with anyone else during the test.
• Do not use headphones or earphones during the test.
• Choose a quiet location with no background noise/distractions.
• Make sure the room is well-lit.
• Mobile phones and calculators are strictly not allowed during the test.

With the right computer system setup, a good internet connection, a proper dress code, and an environment conducive to taking the test without any distractions or prohibited devices.

Getting a job at Infosys requires meeting several important requirements related to your education, application materials, computer setup, and testing environment. Candidates should have a Btech degree with good grades as the minimum qualification, no failed courses, and no long breaks in their studies. Candidates should be from tier-1 educational institutions. Infosys Eligibility Criteria for freshers and experienced is added in this blog.

Candidates should submit the original mark sheets, resumes, photos, and a valid ID. You also cannot have been interviewed with Infosys recently. Your computer needs a webcam, updated processor and browser, reliable internet, and backup power for the Infosys exam to be taken from home. You should follow strict rules like dressing professionally, not talking to others, eliminating noise and distractions, having good lighting, and not using prohibited devices like phones or calculators.

By ensuring you meet all of these criteria related to your academics, documentation, computer system, and test setting, you increase your likelihood of success in getting a job offer from Infosys.

Important Links -Infosys Eligibility Criteria 2024

1. Infosys Hiring Process 2024-Roles, Process, and Opportunities
2. Infosys Application Form 2024-Apply Now, Application Link
3. Infosys Salary in India 2024-Freshers and Experienced
4. Infosys Exam Syllabus and Exam Pattern 2024 – PDF Download
5. Top 10 Infosys Coding Questions and Answers
6. How to Prepare For Infosys Exam 2024- Tips and Strategies
7. Infosys Previous Year Paper-Download PDF With Answers
8. Infosys Hiring 2024- Infosys Exam Date, Eligibility Criteria, Exam Pattern

Infosys Eligibility Criteria For Freshers – FAQs

Hridhya Manoj

Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together

Table of Contents

Infosys Recruitment Process 2024

Infosys is a big IT company that will hire many new people in 2024. Getting a job at Infosys is a great opportunity for those interested in working in technology. The recruitment process has different steps to check if candidates have the right skills and knowledge. First, the online exam test will evaluate your logical thinking, technical, and mathematical abilities. Those who pass get called for interviews where Infosys checks their technical skills, communication, teamwork, and problem-solving.

However, these interviews are challenging but give candidates a fair chance to prove themselves. Overall, the Infosys 2024 recruitment is a tough but rewarding process for finding talented people who can grow their careers with this leading tech company. This blog is about the Infosys Recruitment Process 2024.

Infosys Recruitment Process

The Infosys recruitment process is listed below. Candidates can check it out

Online Test

The online test is the initial step in the Infosys Recruitment Process. It will be conducted for an hour in a particular center for the examination. This online test will check the candidate’s skill-on, Verbal, Logic, and Pseudo Code. Each section should be completed within the time limit.

Practice for Infosys Exam with Skillvertex mocktest

Technical Interview

The technical interview is an important part of the Infosys hiring process. In this round, candidates are tested on their technical knowledge and skills. The interviewer may ask questions, about programming languages, data structures, algorithms, and other computer science concepts. They may give the candidate a coding problem during the interview. The interviewer wants to see if the candidate has strong problem-solving abilities and also check if the candidate can write clean, efficient code. The technical interview tests a candidate’s practical skills in software development.

HR Interview

The HR Round will be conducted in the last stage of the hiring process. This will be mostly face-to-face interaction with HR. If the candidate clears the round, they will be given the offer letter with the joining date. HR Round is considered the most tricky and challenging round. Therefore, candidates should prepare for this round while preparing for the Technical round conducted by Infosys.

What are the Infosys Job Roles?

Candidates can check the job roles listed by Infosys and the career opportunities. They should understand the Infosys Recruitment Process and the job roles to prepare for the Infosys Exam. The Infosys job roles below are open for hire. Interested candidates can check the Infosys official website and start applying.

1. Transformation Strategist

As a transformation architect, your key responsibility is to lead cloud computing.

• You will create a comprehensive cloud adoption strategy,
• They will figure out how to transition different systems and applications to the cloud. This includes selecting cloud platforms and planning their operations.
• You’ll work closely with business and tech experts to develop this strategy.
• You’ll oversee its execution by defining the technical architecture and providing governance.
• Strong communication skills and the ability to bridge business needs with technical solutions will be essential in this role. Your expertise will drive a smooth cloud transformation across the company.

2. Service Assurance

Service Assurance involves ensuring the quality and reliability of services provided to customers.

• As a Service Assurance expert, you’ll monitor service performance, identify issues, and implement solutions to maintain high service levels.
• Product SMEs (Subject Matter Experts) have deep domain knowledge of specific products or technologies.
• You’ll provide technical guidance, training, and support to ensure effective product implementation and usage.
• Process Designers analyze and redesign business processes for optimization.
• You’ll map out current processes, identify inefficiencies, and design improved workflows leveraging best practices and automation.
• Strong process modeling, analysis, and communication skills are crucial.

These skills encompass assuring service quality, providing specialized product expertise, and streamlining processes for enhanced productivity and customer experience.

3. Mainframe Testing_IHLCP

As an Infosys consultant, your day-to-day responsibilities involve:

• Assisting the consulting team across all phases of client projects
• Clearly defining the problem or challenge faced by the client
• Estimating the effort needed to address the issue
• Analyzing and diagnosing the root causes behind the problem
• Suggesting and designing potential solutions
• Helping implement and deploy the recommended solution for the client

4. Mobile Testing, API Automation – IHLCP

As an Infosys consultant, your daily role involves:

• Working closely with the consulting team on client projects
• Clearly defining the client’s problem or challenge
• Estimating the effort required to solve the problem
• Analyzing and diagnosing the root causes
• Suggesting potential solutions
• Designing how to implement the recommended solution
• Assisting in deploying the solution for the client

5. Performance TestingLoad Runner/Jmeter/ Neoload – IHLCP – PAN India

A day in the life of an Infosys consultant involves

• Helping the team with different parts of a project
• Figuring out problems, estimating work, finding causes
• Suggest solutions, and implement fixes.

Infosys Career Opportunities And Benefits

Infosys is a top global company in digital services and consulting. We have over 300,000 employees who work to help people, businesses, and communities succeed. We assist clients in over 56 countries to adapt to the digital world. With over 40 years of experience, we’re experts in managing global businesses. We guide clients through their digital transformation using cloud and AI technologies. We focus on using AI, making businesses agile, and promoting continuous learning. We’re committed to being a well-run, environmentally friendly company where everyone can succeed. Graduates can check out the career opportunities while checking the Infosys recruitment process.

Additional Benefits offered by the Infosys is given below:

• Financial, Retirement, and Performance bonuses.
• Child Care, Parental Leave, Childcare benefits, and Family medical leave.
• Office Perks and Company-sponsored outings.
• Health Insurance, Wellness which includes Dental insurance.
• Professional Growth, Job training & conferences.
• Vacation, Time Off, and includes Paid holidays.
• Infosys also provides a Remote work program.

In conclusion, the Infosys recruitment process in 2024 offers exciting opportunities for individuals to join a global leader in digital services and consulting. With over 300,000 employees worldwide, Infosys is committed to amplifying human potential and fostering innovation. Aspiring candidates can look forward to a diverse and inclusive workplace where they can contribute to navigating digital transformations for clients across more than 56 countries. By focusing on cloud and AI technologies, Infosys empowers its employees to drive continuous improvement and make a meaningful impact on businesses and communities in this world.

Furthermore, this blog has listed the Infosys recruitment process for 2024, roles, and opportunities for your reference. This step-by-step Infosys recruitment process added here will improve your knowledge about the recruitment process and provide you with the rules and regulations for the Infosys online exam.

Important Links – Infosys Recruitment Process2024

1. Infosys Hiring 2024- Infosys Exam Date, Eligibility Criteria, Exam Pattern
2. Infosys Exam Syllabus and Exam Pattern 2024 – PDF Download
3. Top Infosys Interview Questions and Answers For 2024
4. Infosys Application Form 2024-Apply Now
5. Infosys Previous Year Paper-Download PDF With Answers
6. Top 10 Infosys Coding Questions and Answers
7. Infosys Eligibility Criteria For Freshers And Experienced 2024
8. Infosys Salary in India 2024-Freshers and Experienced

Infosys Hiring Process – FAQs

Hridhya Manoj

Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together