To resolve this issue, you have a few options:

1. Add @JsonIgnoreProperties Annotation: You can annotate your Java class with @JsonIgnoreProperties(ignoreUnknown = true). This tells Jackson to ignore any unrecognized fields in the JSON data.

   @JsonIgnoreProperties(ignoreUnknown = true)
   public class YourObject {
       // Your class fields
   }

2. Add Field Mapping: Ensure that your Java class has fields that match the fields in your JSON data. You can use annotations like @JsonProperty to map the JSON field names to your Java class fields.

   public class YourObject {
       @JsonProperty("jsonFieldName")
       private String javaFieldName;
       // Other fields
   }

3. Remove Unneeded Fields: If you don’t need some of the fields in your JSON data, you can simply remove them from the JSON string before parsing it.
4. Use a Custom Deserializer: In more complex cases, you can create a custom deserializer to handle JSON data that doesn’t map directly to your Java class.

The exact solution depends on your specific use case and how you want to handle the unrecognized fields in your JSON data.

Hridhya Manoj

Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together