i = 0
while i < 5:
print(i)
i += 1
if i == 3:
break
else:
print(0)
A) 0 1 2 0
B) 0 1 2
C) error
D) None of the mentioned
Correct Answer: (B). 0 1 2
What Will Be The Output Of The Following Python Code
The given Python code is a while loop that prints the value of i
in each iteration until i
becomes equal to 3. Let’s break down the code step by step:
i = 0
– Initialize the variablei
with the value 0.- The while loop starts:
- The condition
i < 5
is checked. Sincei
is initially 0, this condition is true. - The code inside the loop is executed:
print(i)
prints the current value ofi
, which is 0.i += 1
increments the value ofi
to 1.- The condition
i == 3
is checked. Sincei
is now 1, this condition is false.
3. The loop repeats:
- The condition
i < 5
is checked. Sincei
is now 1, this condition is true. - The code inside the loop is executed:
print(i)
prints the current value ofi
, which is 1.i += 1
increments the value ofi
to 2.- The condition
i == 3
is checked. Sincei
is now 2, this condition is false.
4. The loop repeats:
- The condition
i < 5
is checked. Sincei
is now 2, this condition is true. - The code inside the loop is executed:
print(i)
prints the current value ofi
, which is 2.i += 1
increments the value ofi
to 3.- The condition
i == 3
is checked. Sincei
is now 3, this condition is true. - The
break
the statement is executed, which immediately exits the loop.
5. The loop ends.
So, the output of the code will be:
0
1
2
Hello, I’m Hridhya Manoj. I’m passionate about technology and its ever-evolving landscape. With a deep love for writing and a curious mind, I enjoy translating complex concepts into understandable, engaging content. Let’s explore the world of tech together